+ محدودیت زمان: ۱۰ ثانیه
+ محدودیت حافظه: ۲۵۶ مگابایت
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Cafe Bazaar, the famous Iranian android market, is looking for creative software developers. A group of applicants are attending an interview, and the company wants to select the fastest developer who can code simple rules accurately. As a test, all applicants should quickly develop a bank card verifier that determines whether a payment card number is valid or not.
All payment card numbers are 16 digits long. The leftmost 6 digits represent a unique identification number for the bank who has issued the card. The next 2 digits determine the type of the card (e.g., debit, credit, gift). Digits 9 to 15 are the serial number of the card, and the last digit is used as a control digit to verify whether the card number is valid. Hence, if somebody enters the card number incorrectly, there is a high chance that a payment software can easily determine it.
For a valid card number, the last digit is selected in such a way that the following algorithm passes:
1. Label all digits from left to right by 1 to 16.
2. Multiply each odd-labeled digit by 2.
3. If the result for any digit is greater than 9, subtract 9 from it.
4. Sum the results of the previous step, and add to it the sum of all even-labeled digits.
5. If the result is a multiple of 10, the card number is valid; otherwise, it is invalid.
Your task is to read several card numbers from the input, and determine whether each one is a valid card number or not.
# ورودی
There are multiple test cases in the input. Each test is given in one line consisting of four space-separated 4-digit strings. The leftmost digit of the given card number is guaranteed to be non-zero. The input terminates with a line containing `0000 0000 0000 0000` that should not be processed.
# خروجی
For each test case, output a line containing `Yes` or `No` depending on whether the card number is valid or not, respectively
# مثال
## ورودی نمونه ۱
```
6104 3376 7866 1545
6104 3376 7866 1546
5022 2910 0140 7954
0000 0000 0000 0000
```
## خروجی نمونه ۱
```
Yes
No
Yes
```